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A Calculus question. Consider the parabola y=5x-x^2 (a) Find the slope of the tangent line to the parabola at point (1,4) (b) Find an equation of the tangent line in part (a)
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To find the slope, find the first derivative. The first derivative will give you the equation of the tangent line.
What is the derivative of that equation?
I'm not sure. I've gotten as far as plugging in the parabola into the difference quotient: (5(x+h)-(x+h)^2)-(5(x)-(x)^2)/h
I just learned this, this morning and I'm really confused.
Expand the top more to see if it can be simplified
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Ok, the derivative is like this:
|dw:1409968167817:dw|
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