The sum of the ages of a woman and her son is 36 years. Six years from now the woman will be twice as old as her son. How old is she now?
Use algebra to answer Let S be Son's Age Let W be Woman's age S+W=36 W+6=2S
You can then to substitution or subtraction
i dont understand. it has 2 equations?
If you see, it says Son and Woman is 36 years. Therefore S + W = 36, right? Then it says that when the woman's age is plus 6, then it would be twice the son. Therefore Woman + 6 = 2 X Son, W+6=2S
okay. thank you
No problem :D
i have to solve it too...
Whoops, let me try again Equation is: \[s+w=36\] & \[w+6=2s\] Rearrange so it is \[w+s=16\] & \[w+6=2s\] Subtract each other. The W would cancel out \[s-6=16-2s\]
okay i get it now
:D
where did the 16 come from?
Oh, whoops 36. Computer is not working ;)
so s=14 and w=22 but that equals 36 so now i need to do it for six years from now
22+6
Thats how old she would be in 6 years
Thank you! I did it! :)
If you want to make sure, type "s+2=36, w+6=ws" into WolframAlpha. That will give the answers for you to chec
No Problem :D
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