Question

What is the equation of a circle, when the radius is 5 and the points pass through (3, 1) and (-2, -4)

Answer 1

I know the equation is:\[(x-h)+(y-k)=r^2\]
Substituting the radius, I get:\[(x-h)+(y-k)=25\]
I am stuck there

Answer 2

SO whas the p[roblem here....you 0nly need to plug-in the values?

Answer 3

what coordinate you are taking as centre?

Answer 4

The centre is where 5 points away from both (3,1) and (-2,-4)

Answer 5

The answer is this, if that helps\[(x+2)^2+(y-1)^2=25\]

Answer 6

very easy just take any one of the points as reference and u will get the centre point and then plug the values

Answer 7

Sorry, but I am still not understanding using one of the points as reference?
What do you mean?

Answer 8

say you take the P(3,1) As reference and subtract 5 points from it such that twice the point will yield P(-2,-4)...got it?

Answer 9

and then you can get the centre and plug the values then and you will get the answer

nah...you have to make it such that twice the 5 gives you negative coordinates points..and here's the catch..
use the euclidean distance formula........
and construct it

Answer 10

OK, I give up on this question. I don't even know what the euclidean distance formula is. But thanks anyway

Answer 11

hehey..why give up...

euclidean distance means the distance between 2 points in a Cartesian plane:

given by

\[\xi = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\]

They should have taught it to u but haven't give you the 0fficial name

Answer 12

@Ahsome :NEVER GiVE UP

Answer 13

I am in Grade 10. So I don't know

Answer 14

Ok, doing that will give me what number? The Radius?

Answer 15

OK I have made it quite complex instead of using other point as reference(the negative coordinate ones(-2,-4))

just use the positive ones as reference ..and get the coordinates for the centre of the circle (5 [points away)and then use those values to plug in the formula and Voila..you will get the answer

Answer 16

()K I gotta go..I will give you the workin' when I will com back if you will find yarself' unable to do it...just think.....otherwise the wonderful community of OS(including me ..lol) will be there...

Answer 17

I am sorry for being so unreasonable, but I still am not sure. Can you like draw it or something?

Answer 18

K, you go. Whenever you can, please help ;) @Adjax

Answer 19

If you can help @shereenkhan ,please do

Answer 20

i am trying bro :)

Answer 21

Thanks man :D

Answer 22

Come on @iambatman , instead of saving Gotham try to save my Maths B test ;)

Answer 23

@aryandecoolest.
we need help

Answer 24

what formula u were using is for (h,k)---->is co ordinates of the center and radius,r=5.
so it won't be applicable here :P

Answer 25

OH man.....

here's hint
5 = sqrt((x1 -x2) + (y1-y2))
put the values of x1 and y1
you will get the eqn.

x +/- y = something(+/- denotes I'm not sure of what symbol will come after operation)

repeat the step once more with the other point (-2,-4)

and you willl get again

x /- y = somethijng

I assume you know about simultaneous EQNs. and solving them(Since you are 10th grader)

=> x +/- y = something
x +/- y = something
-------------------
______________________

you will get the value of any one and using anyone you can find the other variable and voila..you'll get the answer

Answer 26

remember the euclidean distance formula it's the key

Answer 27

@Ahsome

Answer 28

hello @Adjax its not the way to solve it.. it lil tricky

Answer 29

two points on circle are given .. putting in (x-h)2+(y-k)2=r2
you have to putt these points and radius and get two equations in variables h and k
so to solve them u have to find out the center of circle

Answer 30

after finding center (h,k) u can find out equation of circle ..

Answer 31

so radius value lena hai.

Answer 32

okay :)
ous ke baath.

Answer 33

look u hv to go in thsi direction
(3-h)^2+(1-k)^2=5^2 .... eq1
(-2-h)^2+(-4-k)^2=5^2 .... eq2

Answer 34

in do equations ko simultaneouslu solve kro h & k find kro .. mtlb center (h,k)
then u can find equation by putting radius and center in (x-h)^2+(y-k)^2=r^2
where (h, k) is center and r is radius.. so tahts all Lol!

Answer 35

that's all :)

Answer 36

yea

Answer 37

okay :)

Answer 38

sahe kahu mere upper se chala gaya :)

Answer 39

i mean ser k upper se :)

Answer 40

easy c bt hy .. 2 points pata hen circle pr .. or radius b .. ab is sb ki help se hm ne center find out krna hy .. itan to smjh lg ra hy na ??

Answer 41

q k circle ki equation k lye hmen just 2 chezen pta honi chahye .. aik center (h,k) or aik radius ... and radius to provided hy lakin center ni hy .... to sb se phle socho k center kese find out kren

Answer 42

h,k ke value lena hai.
right:)

Answer 43

u knw.. (x_h)^2_(y-k)^2=r^2 is me radius or 1st point put kren to u can have equation in form of h and k ... ryt
issi terha radius or 2nd point putt krne se h or k me 2nd equation mil jye gi .....
ab in dono h k ki equations ko solve krne se hmen h or k ki values mil jyen gi

Answer 44

yup ryt

Answer 45

iss k baath i am blank.

Answer 46

ab center find kr lo gi na h and k ???

Answer 47

jb yeh find kr liya na to center ki equation (x-h)^2+(y-k)^2=r^2
h k ki wavlues or radius ki value put kr k equtaion nikal lena simple

Answer 48

hw to find a center point

Answer 49

arey yra .. h, k center he hy

Answer 50

R(h,k) its center

Answer 51

toh ous ka value kise nikalu.

Answer 52

to oper mene phr se kia btaya hy
woh smjho

Answer 53

fist equ... ku 2equ... ku kiya karu.

Answer 54

ku k equation 2 veriables me ho gi h and k ....... so h and k ikathe aik he equation me kese solve kro gi us k lye 2 equations zaroori hen ..

Answer 55

koin sa yeh (-2-h)^2+(-4-k)^2=5^2

Answer 56

@khurramshahzad :

I can't get you correctly ..what language you are speaking(I used google but no language is detected)...BUt what I've got from yar working is quite right..
But my method is also not wrong ..

As you already described your method is little tricky(not much but yes it is for the Asker) ...I just simplified my approach 'cuz I think that the @Ahsome is having a little trouble....

Answer 57

yup is ko solve kro to h^2 and k^2 ki form me equation aye gi wahan se h ko seperate jrna

Answer 58

and can you summarize all yar' working in one post..it will be better....

Answer 59

mmm @Adjax did u see my 2nd comment .. it will tell u the direction of questions. i went through very simplified way

Answer 60

I meant that a summarized post will l00k much better and will be easy to digest and I can't understand some of yar' post..I can only got some bits right...

Answer 61

wht did u said @khurramshahzad

Answer 62

and the method I described in some indirect forms thought very simple is used for the same purpose such as finding a distance between object in computer gaming....

Answer 63

(-6-h)^2+(-4-k)^2=5^2

Answer 64

two points on circle are given .. putting in (x-h)2+(y-k)2=r2
you have to putt these points and radius and get two equations in variables h and k
so to solve them u have to find out the center of circle
after finding center (h,k) u can find out equation of circle ..
look u hv to go in thsi direction
(3-h)^2+(1-k)^2=5^2 .... eq1
(-2-h)^2+(-4-k)^2=5^2 .... eq2

solve these 2 equations simultanously and find h and k taht will be center (h,k)
then u can find equation by putting radius and center in (x-h)^2+(y-k)^2=r^2
where (h, k) is center and r is radius.. so tahts all Lol!

u hv two points on circle .. and radius .. now find out center h and k
thats center .. then using center and radius you will hv teh required equation

Answer 65

okay @Adjax may be u are right too.. actually i did not get ur meanings

Answer 66

anyway...there are 100 ways to get to destiny....l0lz ./.:+UP

Answer 67

lol!

Answer 68

and that language is urdu .. i thought we all were urdu speaking on this qeuestion :D