Question

The probability that there is a quiz today is .62. The probability that a student leaves a calculator in the classroom given that there is a quiz today is .34. The probability that a student does not leave a calculator behind given that there is no quiz today is .94.

What is the probability that a student leaves a calculator in class?
So far I know that I would set it up like P(H given C)
Also like what is the Bayes's Rule used for? Is it for in this type of situations?

Answer 1

@Hero @satellite73 @zepdrix do you guys think you can help with this probability problem?

Answer 2

@kohai ??? :)

Answer 3

yay! :) @kohai

Answer 4

Ehhhh probability is not my strong point, I'm actually terrible with it and I'm not really comfortable trying to help

Answer 5

oh okay

Answer 6

I'm really sorry :(

Answer 7

@kohai it's okay! @satellite73 plzzzz... do you think you can help? :) It's probability.

Answer 8

@xapproachesinfinity do you think you can try :)

Answer 9

let me see!

Answer 10

i am sure we can do this
takes a minute to think

Answer 11

Yes! we can^_^

Answer 12

yess! thank you! :)

Answer 13

let's think about it this way! i always prefer it like this
set A event that he leaves a calculator
B event that there is a quiz alright

Answer 14

I say we should use bayes's rule...

Answer 15

well see about that!

Answer 16

will*

Answer 17

Now
we are concerned about P(A/B), yes?

Answer 18

yes..I think

Answer 19

meaning probability of A happening given that B happened
recall that B is event that there is a quiz

Answer 20

ahh.. I see