A rain gutter is to be constructed of aluminum sheets 12 inches wide. After marking off a length of 4 inches from each edge, this length is bent up at an angle Θ. The area A of the opening may be expressed as the function: A(Θ) = 16 sin Θ • (cos Θ + 1). If Θ = 60°, what is the area of the opening? 1.2 in2 7.9 in2 16.3 in2 20.8 in2
i saw this, and cried a little.
I do that for every math problem...
Thats how i feel alot ;-;
I'm so sorry. :(
Good news, they used a lot of words that they didn't need, it's a simple plug in problem
Is it? ;c
Yes indeed.
The question is to find the area when the angle is 60. But they give us the formula to calculate the area in the previous sentence!
A(Θ) = 16 sin Θ • (cos Θ + 1) plug in Θ = 60* or pi/3 radians and solve!
SOOOO. Wait a second,
A(t) = 16 sin t ( cos t + 1) when t = pi/3
OOO. Wait, how am i supposed to solve that. ;-;..
Well, its using function notation, let me make it easier to interpret, they mean: Area = 16 sin(pi/3) ( cos(pi/3) + 1) that's all
you only need to calculate the right hand side
Oh. So. Like.... We convvert cos(pi/3) into Sqrt3/2?
well, cos(pi/3) is 1/2, but yeah, that's the idea. :)
OH. I Was close.
:)
So. 1/2+1?
on the inside of the parentheses good
1.5? I Think. im doing this mentally.
Yes, we have 16 sin(pi/3) * 1.5 so far.
Oh Gawd. ;-;
Want me to multiply them out on a calculator for you? :)
Please c:
20.78
SO ITS D ;O
YES!
Omggg One MOREEEEEE.
Almost there!
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