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Mathematics 19 Online
OpenStudy (anonymous):

Write the standard equation of the circle below.

OpenStudy (anonymous):

OpenStudy (unklerhaukus):

The form is \[(x - h)^2 + (y-k)^2 = r^2\] when \((h, k)\) is the centre of the circle, and \(r\) is the radius. What are \(h,k,r\) for this circle ?

OpenStudy (anonymous):

I got (x + 2)^2 + (y - 1)^2 = 9 ?

OpenStudy (unklerhaukus):

try again

OpenStudy (unklerhaukus):

\(h\) is the \(x\)-coordinate of the centre

OpenStudy (anonymous):

(x + 1)^2 + (y - 2)^2 = 3?

OpenStudy (ahsome):

@UnkleRhaukus Remember, \(h\) is the NEGATIVE value for \(x\)

OpenStudy (ahsome):

If \(x\) is 5, then \(h\) is -5

OpenStudy (ahsome):

(I think)

OpenStudy (unklerhaukus):

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OpenStudy (unklerhaukus):

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