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3/x+5/x+2=2
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\[\frac{ 3 }{ x }+\frac{ 5 }{ x+2 }=2\]
3(x+2)+5x/x(x+2)=2
3x+6+5x/x^2+2x=2
3x+6+5x=2(x^2+2)
thanks
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so it would be 2x^2-4x-6?
3x+6+5x=2x^2+4 -2x^2+7x+2=0 use the formula \[-b \pm \sqrt{b ^{2}-4ac}/2a\] a=-2 b=7 c=2 plug in the values.
its 8x and 4 x?
-2x^2 +8x+2
2x^2+4
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2x(x+2) dont u have to distribute?
wait i guess i messed up
3x+6+5x=2(x^2+2x) 3x+6+5x=2x^2+4x -2x^2+3x-4x+5x+6=0 -2x^2+4x+6=0
yeah thats what i got
then i plug it back to the formula?
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i just missed that x....now can u plug in the values of a,b and c in the formula
yes,a=-2,b=4 and c=6
i got -1 and 3
the answer is just -1 and 3?
or do i put x=-1,3
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can u show ur work
wait
yes the roots are -1 and 3
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