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Mathematics 22 Online
OpenStudy (anonymous):

3/x+5/x+2=2

OpenStudy (anonymous):

\[\frac{ 3 }{ x }+\frac{ 5 }{ x+2 }=2\]

OpenStudy (cj49):

3(x+2)+5x/x(x+2)=2

OpenStudy (cj49):

3x+6+5x/x^2+2x=2

OpenStudy (cj49):

3x+6+5x=2(x^2+2)

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

so it would be 2x^2-4x-6?

OpenStudy (cj49):

3x+6+5x=2x^2+4 -2x^2+7x+2=0 use the formula \[-b \pm \sqrt{b ^{2}-4ac}/2a\] a=-2 b=7 c=2 plug in the values.

OpenStudy (anonymous):

its 8x and 4 x?

OpenStudy (cj49):

-2x^2 +8x+2

OpenStudy (anonymous):

2x^2+4

OpenStudy (anonymous):

2x(x+2) dont u have to distribute?

OpenStudy (cj49):

wait i guess i messed up

OpenStudy (cj49):

3x+6+5x=2(x^2+2x) 3x+6+5x=2x^2+4x -2x^2+3x-4x+5x+6=0 -2x^2+4x+6=0

OpenStudy (anonymous):

yeah thats what i got

OpenStudy (anonymous):

then i plug it back to the formula?

OpenStudy (cj49):

i just missed that x....now can u plug in the values of a,b and c in the formula

OpenStudy (cj49):

yes,a=-2,b=4 and c=6

OpenStudy (anonymous):

i got -1 and 3

OpenStudy (anonymous):

the answer is just -1 and 3?

OpenStudy (anonymous):

or do i put x=-1,3

OpenStudy (cj49):

can u show ur work

OpenStudy (cj49):

wait

OpenStudy (cj49):

yes the roots are -1 and 3

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