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OpenStudy (anonymous):
((8x+13)+(x2-5x))(x) how would you solve for that???
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OpenStudy (abb0t):
Distribute the "x" first.
OpenStudy (anonymous):
I thought whatever is in the parentheses, is like solved first?
OpenStudy (mathstudent55):
Is this the multiplication of the quantity and x?
\( \large [(8x+13)+(x^2-5x)]x\)
OpenStudy (anonymous):
i do not think so
OpenStudy (mathstudent55):
Then what is the problem?
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OpenStudy (anonymous):
OpenStudy (anonymous):
Btw, its problem number 2
OpenStudy (mathstudent55):
I got it.
OpenStudy (mathstudent55):
Here are the two functions f and g.
\(f(x) = 8x + 13\)
\(g(x) = x^2 - 5x\)
2.
\((f + g)(x) = f(x) + g(x)\)
\((f + g)(x) = 8x + 13 + x^2 - 5x\)
\((f + g)(x)= x^2 + 3x +13\)
OpenStudy (mathstudent55):
All you need to do for 2. is to add the functions f and g.
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OpenStudy (anonymous):
ooooh okay, THANKYOU SO MUCH!!
OpenStudy (mathstudent55):
You're welcome.
OpenStudy (anonymous):
what about number 11? How would you find the composite function?
do you plug in and solve or something else?
OpenStudy (mathstudent55):
For composite functions, plug in the inner function into x of the outer function.
11.
\(f(g(x)) = f(2x - 3) = (2x - 3)^2\)
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