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The perimeter of a rectangular garden is 114 meters. The length is 6 meters longer than twice the width. Find the dimensions of the garden.
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We know that the equations for the perimeter of a rectangle is P=2l+2w . l being lenght and w being width
So now we will substitute what we are given into that equation
p=114 L=6+2w
114=2(6+2w)+2w
So with some simplification and combining like terms and a little algebra we come to 114=12+6w 102=6w w=6
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And since we know W we can easily find the length
so it would be 114=2l+6?
Close but in the perimeter equation it is p=2L+2w so it would be 114 =2L+2(6)
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