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yes?
(6/y+5)-(9/y-5)=(15/y^2-25) a.-30 b.90 c.64 d.30
i keep getting 45.923
let me try it out first
Is this the problem? \(\dfrac{6}{y+5}- \dfrac{9}{y-5}= \dfrac{15}{y^2-25}\)
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yes
Start by factoring the last denominator. What do you get?
-4*6*sqrt(6)*a
What? I don't see an "a" anywhere in the problem. Where did you get "a" from? Just factor \(y^2 - 25\) It's the difference ff two squares.
Use this to factor the third denominator. \(a^2 - b^2 = (a + b)(a - b)\)
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Sorry, gtg. It's late.
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