Question

evaluate:
1.) (-3y^5) (-7y^4)
2.) 5a^-8 b^4
3.) pq^-3 r^-4 / 3u^-5
4.) 14x^-2 yz^-4 / 2xyz

Answer 1

You have to solve all of these? @lyssaaaa

Answer 2

yep it's actually up to ten but nah I think I can do the others

Answer 3

(-3y^5)(-7y^4) For the first one, just multiply -3 and -7, then add the exponents.

Answer 4

That will give you 21y^9

Answer 5

ohhhh

Answer 6

Is the 2nd one multiplication?

Answer 7

I think so. It says 5a raised to -8 b raised to 4 that's it

Answer 8

Oh, do you have choices? Because you can't simplify that anymore..the same goes with the third one..you can't simplify it anymore.

Answer 9

In the fourth one:

14x^-2 yz^-4 / 2xyz

Are 14x^-2 and yz^-4 being multiplied?

Answer 10

It doesn't have choices

Answer 11

Well, just say #2 and #3 are already simplified.

Answer 12

I think I have to simplify it first ?

Answer 13

yep okay how abt num 4

Answer 14

isn't it like 14x^-2 simplify first with 2x?

Answer 15

For the fourth one, just divide 14 by 2, and subtract 1 for every exponent in the numerator.

14x^-2 yz^-4 / 2xyz

That will give us:

7x^-3 z^-5

It cancels out the y-variable.

Answer 16

Ohhh

Answer 17

Yes, you would simplify the 14x^-2 first.

Answer 18

I still have a few questions is it okay ?

Answer 19

For the third one, you can't divide because the denominator doesn't have a similar variable with the numerator.

Answer 20

Yeah, sure.

Answer 21

What abt (5m^-1 n^2) (-3m^3 n)

Answer 22

\((5m^{-1} n^2) (-3m^3 n)\)

Multiply the bases, add the exponents.

\(5 * -3 = -15.\)

\(m^{-1} + m^3 = m^2\)

\(n^2 + n = n^3\)

So:

\(-15m^2n^3\)

Answer 23

Ohhh hb (-3x^-2 y)^-1 u will distribute -1 right?

Answer 24

And last 10^-5 / 10^6 = 10 am I right?

Answer 25

last question promise (-5)^-2

Answer 26

(-5)^-2 = -0.04