Question

Given that f(x) = 3x + 1 and g(x) = the quantity of 4x plus 2 divided by 3, solve for g(f(0)).

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Answer 1

@UnkleRhaukus can you help

Answer 2

can you turn the expression for g(x) into mathematical symbols

g(x) = the quantity of 4x plus 2 divided by 3
=

Answer 3

g(x)=4x+2/3

Answer 4

' the quantity ' bit means you need some parenthesis

g(x)=(4x+2)/3

Answer 5

The question is looking for g(f(0))

lets find f(0) first;

f(x) = 3x + 1

subbing in zero for x, we get

f(0) = 3(0) + 1
= what does this simplify to ?

Answer 6

f(0)=4

Answer 7

no wait not 4

Answer 8

1

Answer 9

careful that 3(0) really mean 3 x 0

Answer 10

yeah f(0) = 1

Answer 11

so all we have left to do is find
g(f(0)) = g(1)

and we already have

g(x) = (4x+2)/3

so sub in x=1

g(1) =

Answer 12

g(1)=(4(1)+2)/3
=(4+2)/3
= 6/3
=2
g(1)=2

Answer 13

\[\huge\color{red}\checkmark\]

Answer 14

thank you

Answer 15

good work