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This is a differential equation of 2nd order, I need to find a function that if substituted on both sides will be equal d2xdt2=−ω2x
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\[\frac{ d ^{2}x }{ dt ^{2}} = \omega ^{2} x\]
omega squared, or minus omega squared ?
minus omega squared sry
no problem suppose you have a function f(x) = sin(x) what is df/dx ?
0?
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No : ( You should read up a bit on differentiating sines and cosines then come back to your differential equation question
Okay will do, thanks anyways :)
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