Question

FIND THE PRIME FACTORIZATION OF 4620. help please.

Answer 1

Since your number ends in 0: it's easy to divide by 10:

\(4620 \div 10=462\) and you know the prime factors of 10 are 5 and 2
(Keep 5 and 2 in mind)

Now you have an even number, so divide by 2:
\( 462 \div 2=231\)
(keep 2 in mind)

Now I notice that 231 is divisible by 3 since 2+3+1=6, a number divisible by 3 (this is one of the tricks to know which numbers are divisible by 3)
\(231 \div 3 = 77\)
(keep 3 in mind)

Now hopefully you notice that you have double repeating digits, meaning this is a multiple of 11:
\(77 \div 11 = 7\)
(keep 11 and 7 in mind)

So, your factors:
\(2^2\times 5 \times 3 \times 7 \times 11\)

Answer 2

2 * 2 * 3 * 5 * 7 * 11