Question

y'+y=0 find a general solution

Answer 1

I got \[y=c e^t\]

Answer 2

but the answer is \[y=ce^{-t}\] I don't know how

Answer 3

Careful with negatives. It's seperable.

Answer 4

So dy/dt= -y

Answer 5

Try now.

Answer 6

how to do it? Integration factor is \[e^{A(t)}, A(t)=\int\limits_{}^{}a(t) dt\]

Answer 7

This is not a linear equation.

Answer 8

it is homogeneous

Answer 9

linear 1st order