jim drove to friends house at a Rate of 50mi/hr. he returned by the same route at 45mi/hr. The driving time for the round trip was 3 hrs. what is the distance jim travelled
I would make a table like this:|dw:1410232088374:dw|
We know the rates to put in there. 50 mph going and 45 mph coming back.
|dw:1410232178529:dw|
We also know that the distance there is equal to the distance back, although we do not know what that distance is. Not important. Fill it in like this:
|dw:1410232235354:dw|This indicates the distance is the same both ways.
If the round trip was 3 hours, going there would be "t", and coming back would be 3 - t. So that goes in like this:
|dw:1410232305651:dw|
Now, since the distances are the same, we can solve each for d and then set them equal to each other. For the distance formula, d = rt, so that translates to this for our equations.
|dw:1410232363898:dw| and t = 1.4
Now sub in that 1.4 for the t in the first equation and solve it for d. d = 50(1.4), and d = ?
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