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Write the equation of the quadratic function with roots -1 and -7 and a vertex at (-4, 7)
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Have you seen turning point form before?
\[y=(x-h)^2+k\]
More generally, there should be an \(a\) as well \(y=a(x-h)^2+k\), where \((h, k)\) is the vertex, so you already have this from your problem A root is value of \(x\) when \(y=0\). So if one root is -1, that means you have a coordinate of \((-1, 0)\) You should substitute the root coordinates into your function which will allow you to solve for \(a\).
Haha, whoops, forgot the 'a' :)
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