A student performed the following steps to find the solution to the equation x^2+14x+48=0. Where did the student go wrong?

Step 1. Factor the polynomial into (x + 8) and (x - 6)
Step 2. x + 8 = 0 and x - 6 = 0
Step 3. x = -8 and x = 6

A.in Step 2
B.in Step 1
C.in Step 3
D.The student did not make any mistakes, the solution is correct

Question

A student performed the following steps to find the solution to the equation x^2+14x+48=0. Where did the student go wrong?

Step 1. Factor the polynomial into (x + 8) and (x - 6)
Step 2. x + 8 = 0 and x - 6 = 0
Step 3. x = -8 and x = 6 

A.in Step 2 
B.in Step 1 
C.in Step 3
D.The student did not make any mistakes, the solution is correct

myininaya · Answer

So let's discuss the first step...

myininaya · Answer

It's look at x^2+14x+48

myininaya · Answer

Like without looking at their factors,
how would you attempt to factor this?

myininaya · Answer

Or 
Like could you tell me what two numbers multiply to be 48 and also add up to be 14?

myininaya · Answer

numbers (and the type of number I mean is integer)

anonymous · Answer

it would be (x+8) (x+6) right

myininaya · Answer

right 
so you just said she went wrong in the first step

anonymous · Answer

oh ok thank

myininaya · Answer

You do see why?
she put (x-6) instead

myininaya · Answer

or he

anonymous · Answer

yea and it would be $$x^2+2x-48=0$$ right?

myininaya · Answer

you are totally right !

anonymous · Answer

thank you for your help

anonymous · Answer

:)