Question

Anyone help out with this quick algebra 1 problem. I quite don't understand how to make the equation. I just want the explanation to the answer.

Answer 1

A collection of 40 nickels and quarters has a value of $6.40. How many are there of each kind?

Answer 2

This is what I got .5x+.25x=40

Answer 3

which is wrong...

Answer 4

x+y=40
0.05x+0.25x=6.40

I'm pretty sure this is the right setup. Then just solve the system of e

Answer 5

*system of equations.

Answer 6

oops, for the second equation it should be 0.05x+0.25y. I'm sorry for my typo.

Answer 7

opps, could you write in a one step equation

Answer 8

0.25x+0.1y=6,4

Answer 9

do u get this

Answer 10

and then the second one is x+y=40

Answer 11

Use substitution method

Answer 12

n = number of nickels
5n = value of the nickels in cents
q = number of quarters
25q = value of the quarters in cents
.
n+q = 40
n = 40-q
.
5n + 25q = 640 cents
.
substitute
.
5(40-q) +25q = 640
200 -5q +25q = 640


20q = 440
q = 22
.
n = 40-22
n = 18
.
check the values to be sure this is the correct answer
.
25(22) = 550 cents
5(18) = 90 cents
550 + 90 = 640 cents = $6.40

Answer 13

x=40-y
0.25(40-y)+y=40

Answer 14

solve

Answer 15

Okay, well, you just combine equations real quick. The number of nickels is x, and the number of quarters is (40-x).
So write it as 0.05x+0.25(40-x)=6.40. Then solve for x.

Answer 16

That should help and explain a little bit

Answer 17

@Brandonsnider188 thats a lot more complicated though

Answer 18

Not really.

Answer 19

It's pretty much what you guys are saying but summed up X)

Answer 20

yes it is mine is 3 steps

Answer 21

oops didn't notice sry

Answer 22

Yeah, we both said the same thing in different ways.

Answer 23

thanks man :D @Brandonsnider188