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Find the exact value of tan^2 30º - csc^2 30º.
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=13/3
@Loser66 would you please explain for me how you got it. Thank you :)
sec^2x-tan^2x=1
sec^2x+1=tan^2x sec^2x+1-csc^2x=1+sec^2x-cosec^2x
\[\sec30=\frac{ \sqrt{3} }{ 2 }\]
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and find square of it similarly csc 30=1/sin30 and find square of it and put in equation
@gorv thank you.
I don't know why we have to do something more, I just take tan (30) = \(\sqrt 3\) so that tan^2 (30) =3 and + with \(sec =\dfrac{1}{cos (30)}= \dfrac{1}{\sqrt3/2} =\dfrac{2}{\sqrt3}\) which gives me sec^2 = 4/3 hence tan^2 (30) + sec^2 (30)= 3+ 4/3 = 13/3
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