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OpenStudy (anonymous):
Find the domain of the function.
f(x)= sqrt*6-x
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OpenStudy (anonymous):
@kl0723
OpenStudy (anonymous):
B. (-∞,sqrt*6 ) (sqrt*6 , ∞)
C. (-∞,sqrt*6 ]
D. (-∞, 6]
OpenStudy (anonymous):
@triciaal
OpenStudy (anonymous):
c
OpenStudy (anonymous):
you cant find the square root of a negative and anything bigger than six would do it when plugged into the x value
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OpenStudy (triciaal):
you know the domain is the values of x that will satisfy f(x)
OpenStudy (anonymous):
Complete the square and write the equation in standard form. Then give the center and radius of the circle
x^2 + y^2 - 10x - 8y + 29 = 0
OpenStudy (anonymous):
do ur homework yo
OpenStudy (anonymous):
I have but I got these two questions wrong I just need help on this last question notice theres not 4 answers because, I already got it wrong.
OpenStudy (anonymous):
B. (x - 5)2 +(y - 4)2 = 12 (-5, -4), r = 2 sqrt*3
c.(x - 5)2 +(y - 4)2 = 12 (5, 4), r = 2 sqrt*3
D. (x + 5)2 +(y + 4)2 = 12 (-5, -4), r = 2 sqrt*3
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OpenStudy (triciaal):
does this mean you had choice a and it was wrong?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
c?
OpenStudy (triciaal):
I don't see how the other person above had the square root of a negative
I would take the + and - of rt 6
got it !!
|dw:1410330544879:dw|
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