Question

P(2n+4,3) = 2/3 P(n+4,4)

Answer 1

what is 4,3?

Answer 2

btw apperently the answer is 13? oh and we are dealing with P(n,r) stuff or statististics so n=2n+4 and r=3

Answer 3

(2n+4)(2n+3)(2n+2) = 2/3(n+4)(n+3)(n+2)(n+1)

Answer 4

cancel cmmon factors and solve n ?

Answer 5

i had n = 10

Answer 6

ok give me some time :P gotta solve it to see if i get it

Answer 7

@ganeshie8 would it work the same as 4C3 and use factorial? then equate and solve for n?

Answer 8

for 4C3 we need to divide by r! also so thats an extra i think

Answer 9

but permutation is much simpler :

4P3 = 4x3x2

Answer 10

nPr = n(n-1)(n-2)...(n-r+1)

Answer 11

nCr = [ n(n-1)(n-2)...(n-r+1) ] /r!

Answer 12

so i think combination may give us a messy equation

Answer 13

thanks

Answer 14

are we supposed to get 22n^3+86n^2+74n+78=0 at the end?

Answer 15

(2n+4)(2n+3)(2n+2) = 2/3(n+4)(n+3)(n+2)(n+1)

2(n+2)(2n+3)2(n+1) = 2/3(n+4)(n+3)(n+2)(n+1)

4(2n+3) = 2/3(n+4)(n+3)

Answer 16

http://www.wolframalpha.com/input/?i=solve+4%282n%2B3%29+%3D+2%2F3%28n%2B4%29%28n%2B3%29