Question

Using set builder notation, what is the domain for the function f(x) = 1/x+1 ?

Answer 1

\[f(x) = \frac{ 1 }{ x+1 }\]

Answer 2

what value of x makes the denominator equal to zero?

Answer 3

-1 @jim_thompson5910

Answer 4

you get that by setting the denominator x+1 equal to zero and solving for x

good

Answer 5

this x value makes the denominator zero, so we have to exclude it out of the domain

every other number is allowed because any other number doesn't make the denominator zero

Answer 6

using set builder notation, the domain is...

\[\Large D = \left\{ x|x\in\mathbb{R}, x\neq -1 \right\}\]

Answer 7

this basically says: the domain is the set x such that x is any real number but x can't be -1

Answer 8

ohhhh okay thanks

Answer 9

you're welcome