Using set builder notation, what is the domain for the function f(x) = 1/x+1 ?

Question

anonymous · Answer

$$f(x) = \frac{ 1 }{ x+1 }$$

jim_thompson5910 · Answer

what value of x makes the denominator equal to zero?

anonymous · Answer

-1 @jim_thompson5910

jim_thompson5910 · Answer

you get that by setting the denominator x+1 equal to zero and solving for x

good

jim_thompson5910 · Answer

this x value makes the denominator zero, so we have to exclude it out of the domain

every other number is allowed because any other number doesn't make the denominator zero

jim_thompson5910 · Answer

using set builder notation, the domain is...

$$\Large D = \left\{ x|x\in\mathbb{R}, x\neq -1 \right\}$$

jim_thompson5910 · Answer

this basically says: the domain is the set x such that x is any real number but x can't be -1

anonymous · Answer

ohhhh okay thanks

jim_thompson5910 · Answer

you're welcome