Question

Could someone help me with 2yy'=(y^2)+t-1. I understand its Bernoulli ODE but I just cant make the z substitution to put it into the standard form where i can solve it using linear ODE or separable ODE.

Answer 1

here is a reference:
http://tutorial.math.lamar.edu/Classes/DE/Bernoulli.aspx

i would make substitution
\[z = y^2\]
\[z' = 2y y'\]

Answer 2

thank you I did not see that been doing physics all day and my brain is not working anymore...

Answer 3

to get standard form for Bernoulli equation .... divide by 2y

ok no problem

Answer 4

Can't i just make the substitution and solve for z and substitute back the y?