Question

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Answer 1

Help with Calculator?? :P

Answer 2

Shure wait ill try

Answer 3

is it the tangent at a given point?

Answer 4

at c=1?

Answer 5

well a point is identified by an x and y coordinate like (1,1)

Answer 6

f'(x) gives you the slope of the tangent at x
so when x = 1 the slope is 3(1)^2 = 3

Answer 7

but to get the equation you need to know a point on the line
we can work out the corresponding value of y (f(x) by plugging in x = 1
into x^3 + 1

so y = (1)^3 + 1 = 2

now you need to plug in the slope (m) and the point (1,2) (x1,y1) into the standard form for a line

y - y1 = m(x - x1)

Answer 8

Idk

Answer 9

x1 = 1, y1 = 2, m = 3

y - 2 = 3(x - 1)

simplify this and you have the equation of the tangent line

Answer 10

ok?

Answer 11

ty - i've been doing this on my degree course So you understand what i've done?

Answer 12

I have about 5 minutes

Answer 13

then i must go

Answer 14

sorry gotta go - i'll be back in about 15 minutes