Question

t = 2π √l/g Re-arrange to make l the subject.

Answer 1

in other words solve for l
(this by the way something in physics, but can't remember what it is)
\(t=2\pi\sqrt{\frac{l}{g}}\\\frac{t}{2\pi}=\sqrt{\frac{l}{g}}\)
square both sides
\((\frac{t}{2\pi})^2=(\sqrt{\frac{l}{g}}~)^2\)

Answer 2

continue with the rest!

Answer 3

thanks

Answer 4

welcome