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If a > b and c < 0, then:
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ac>bc a over c > b over c ac<bc none of the above
lets try it with numbers since \(12>6\) and \(-3\) is \(<0\) then what do we know about \(12\times (-3)\) vs \(6\times (-3)\)
what is bigger, \[-36\] or \[-18\]?
-18
so....
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so \[ac<bc\] if you multiply by a negative number the inequality flips
also if you divide
so C
it is always C yes
k thanks
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I bet you could find a counterexample @kballet084 to the statement "it is always C" :p
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