So I have to solve this stumper:
triangle-square=circle
square+triangle=2 circle
circle*square=circle
circle=
square=
triangle=
It's due tomorrow!!!Please help.
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OpenStudy (kkutie7):
If I were you I'd solve two equations for one thing... like circle for example and then plug the others into the one you didn't mess with... if that makes sense
OpenStudy (dangerousjesse):
Okay if circle\(\times\)square=circle then square=1
OpenStudy (dangerousjesse):
Or square could just = 0
OpenStudy (dangerousjesse):
Then all of them could just be 0.
OpenStudy (anonymous):
no they all can't be zero because the second sum is two digit
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OpenStudy (dangerousjesse):
Or
triangle=3
square=1
circle=2
OpenStudy (dangerousjesse):
It's not two digit.
OpenStudy (dangerousjesse):
It's 2\(\times\) circle.
OpenStudy (anonymous):
that's what the problem said
OpenStudy (kkutie7):
triangle-square=circle triangle-square=1
square+triangle=2 circle square+triangle=2(1) square+triangle=2
circle*square=circle square=circle/circle square=1
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