show that in any triangle ABC, c=a(cosB) + b(cosA) (Hint: consider separately the cases where both A and B are acute and where one of them is obtuse.)
@mathmetics your question is wrong OR you have typed it wrong question ? The original question is :- Prove that in triangle ABC :- \[\large \bf cosC=aCosB+bcosA\]
hmmmm....... it is what it says on the proble may be problem is wrong... thx anyway
You need to use the law of cosines such that: Substituting for and for yields: Reducing duplicate factors, yields: Bringing both sides to a common denominator, yields: Reducing duplicate terms and , to the right side, yields: Hence, testing if the expression holds, using the law of cosines, yields that is a valid expression.
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