OpenStudy (anonymous):

3 years ago
OpenStudy (anonymous):

Launch Area:___(1, 2)___ Point A:___(0, 3)___ Point B:___(-3, 0)___ Point C:___(-1, -4)___ 2. Determine the equation of the line, in standard form, that will get your spacecraft from the Launch Area to Point A.

3 years ago
OpenStudy (anonymous):

i know the answer is Y = 3 – x but could you explain the steps

3 years ago
OpenStudy (kobeni-chan):

What are the boxes between 3 and x?

3 years ago
OpenStudy (anonymous):

-

3 years ago
OpenStudy (kobeni-chan):

oh ok I see it now. Well you would just use the slope formula (y-y/x-x) to find the slope, which would turn out to be 1, and then the y-intercept is given, +3

3 years ago
OpenStudy (kobeni-chan):

When put into slope intercept form, it would be y = x + 3 Then you have to convert it to standard form so... Subtract y from each side to get ___ = x + 3 - y Then Subtract 3 from each side So you'll have: x - y = 3

3 years ago
OpenStudy (anonymous):

oh ok could i get help with one more since its like the same question

3 years ago
OpenStudy (kobeni-chan):

Sure lol, I think I did this same question in my class

3 years ago
OpenStudy (anonymous):

4. Determine the equation of the line, in slope-intercept form, that will get your spacecraft from Point B to Point C. Y = -2 x - 6

3 years ago
OpenStudy (anonymous):

can yah show the steps please

3 years ago
OpenStudy (kobeni-chan):

Yes, hold on. Oh and I just went and checked the work that I had submitted when I was on that, I told you the slope for the first problem was 1, but it's actually -1 sorry

3 years ago
OpenStudy (anonymous):

oh ok

3 years ago
OpenStudy (kobeni-chan):

the first one in standard form is x + y = 3

3 years ago
OpenStudy (phi):

for your first question, you say **i know the answer is Y = 3 – x *** that is true. but standard form is Ax + By = C where, if at all possible, A, B, and C are integers, and A is non-negative, and, A, B, and C have no common factors other than 1 in other words, start with y=-x +3 (this is slope-intercept form) add +x to both sides to get x+y = 3 (this matches Ax + By = C, with A=1, B=1 and C=3 )

3 years ago
OpenStudy (anonymous):

i think i understand the concept when you guys put it like that thank you all

3 years ago
OpenStudy (kobeni-chan):

Np :) do you still need help with the problem regarding points b and c?

3 years ago
OpenStudy (anonymous):

what about the second one ??

3 years ago
OpenStudy (anonymous):

yeah plx

3 years ago
OpenStudy (phi):

Point B:___(-3, 0)___ Point C:___(-1, -4)___ first, find the slope. Do you know how to do that ?

3 years ago
OpenStudy (anonymous):

let me think one sec plx

3 years ago
OpenStudy (phi):

slope is change in y divided by change in x find "change in y" then find "change in x" then write the fraction

3 years ago
OpenStudy (anonymous):

-2

3 years ago
OpenStudy (phi):

yes. I assume you can "show your work", which is (0- (-4)) / (-3 -(-1)) = 4 / -2 = -2

3 years ago
OpenStudy (kobeni-chan):

Yup. Now if you fill out a T chart, you can figure out what the y-intercept is.

3 years ago
OpenStudy (anonymous):

-6

3 years ago
OpenStudy (kobeni-chan):

now all you have to do is fill in your data where the variables are y=mx+b y=-2x-6

3 years ago
OpenStudy (anonymous):

oh ok so through all does steps showed how we got y=-2x-6

3 years ago
OpenStudy (kobeni-chan):

yup

3 years ago
OpenStudy (anonymous):

let me try to right it out how it would look one sec

3 years ago
OpenStudy (anonymous):

ok got it thx

3 years ago
OpenStudy (phi):

to find the equation use y - y0 = m(x - x0) where (x0,y0) is a point on the line. If you pick point B Point B:___(-3, 0)___ then x0= -3 and y0= 0 (and m is the slope= -2) y - 0 = -2(x - (-3)) y = -2x - 6

3 years ago
OpenStudy (anonymous):

well that sums stuff up

3 years ago
OpenStudy (anonymous):

thx again have nice day

3 years ago
OpenStudy (kobeni-chan):

have a nice day too c: let me know if you need anymore help since we might be covering the same material

3 years ago
OpenStudy (anonymous):

ok ttyl

3 years ago