Quick question.
One number exceeds another number by 7 and the product of the two numbers is 120. Find the number.
I set it up like
n+n+7=120, but the answers weren't right.

Question

Quick question. 
One number exceeds another number by 7 and the product of the two numbers is 120. Find the number. 
I set it up like
n+n+7=120, but the answers weren't right.

bibby · Answer

break up the statements.

One number exceeds another number by 7 
m = n+7

the product of the two numbers is 120. Find the number. 
m*n=120

anonymous · Answer

(n+7)n=120
n^2+7n=120
n^2+7-120=0
(n-8)(n+15)
n=8 and n=-15?

bibby · Answer

-15*8 $\ne $ 120

bibby · Answer

but 15 would work, eh

anonymous · Answer

yeah, did i work it out wrong then?

bibby · Answer

no, you worked out the quadratic correctly, I'm just unsure on why the answer came out like that

anonymous · Answer

haha weird!

anonymous · Answer

(x)*(x+7)=120     x=8

anonymous · Answer

one number is 8 and the other is 15

anonymous · Answer

depending on what number the question wants

bibby · Answer

oh ok, I see it now

anonymous · Answer

I see it too. Thank you!

anonymous · Answer

welcome good luck to you both :)