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Mathematics 13 Online
OpenStudy (anonymous):

helpp

OpenStudy (anonymous):

OpenStudy (anonymous):

these are the answers i have to match it with 18 all reall numbers 15 2 no real solution -9

OpenStudy (anonymous):

@bibby

OpenStudy (bibby):

1. to undo a square root, square both sides. \(\huge \sqrt{4x+1}=3\) \(\huge \sqrt{4x+1}^2=3^2\) \(\huge 4x+1=9\)

OpenStudy (anonymous):

is it 2?

OpenStudy (bibby):

yeah

OpenStudy (anonymous):

yeaaa lol okay can u help with problem 2

OpenStudy (bibby):

fractional exponents are roots. they work like this: \(\huge a^{\frac{1}{2}}=\sqrt{a}\) \(\huge (a+1)^{\frac{1}{3}}=\sqrt[3]{a}\)

OpenStudy (bibby):

so start by getting the variable we want to isolate on one side

OpenStudy (anonymous):

is example 4 9?

OpenStudy (bibby):

yeah

OpenStudy (anonymous):

-9 rite?

OpenStudy (anonymous):

cause that wa answer they have on here they dnt have a regular 9

OpenStudy (bibby):

\(\large\sqrt{x-6}-3=0\) we want to get 3 on the other side. add 3 to both \(\large\sqrt{x-6}=3\) we want to get ride of the square root so we square both sides \(\large{x-6}=9\) add 6 to both sides \(\large{x}=15\)

OpenStudy (bibby):

my bad

OpenStudy (anonymous):

for promblem 2 did u get 18

OpenStudy (bibby):

\(\large4-\sqrt{7-y}=0\) \(\large4=\sqrt{7-y}\) what comes next?

OpenStudy (anonymous):

-9?

OpenStudy (bibby):

yeah. please do the actual work so that I can see you're learning I hate it when I help people and they haven't taken anything away from it at the end

OpenStudy (anonymous):

okay i was im doing problem 3 now

OpenStudy (anonymous):

problem looks like no solution

OpenStudy (anonymous):

im doing the work now

OpenStudy (anonymous):

okay problem 5 is 18 multiply through by 6 12a^(1/3) = 6 divide by 12 a^(1/3)=1/2 cube both sides a=(1/2)^3=1/8

OpenStudy (anonymous):

@bibby

OpenStudy (bibby):

maybe. lemme see \(\huge 1+\sqrt{x+2} =0\) \(\huge \sqrt{x+2} =-1\) \(\huge \sqrt{x+2}^2 =-1^2\) \(\huge {x+2} =1\) \(\huge {x} =-1\)

OpenStudy (bibby):

also nice job on 5. looks right*

OpenStudy (anonymous):

thank now for a reward can u give me problem 3 lol

OpenStudy (anonymous):

@bibby

OpenStudy (bibby):

it's literally the post right above "also nice job

OpenStudy (anonymous):

no solution

OpenStudy (anonymous):

@bibby

OpenStudy (bibby):

I posted the solution right there man

OpenStudy (anonymous):

all real numbers got it lol @bibby

OpenStudy (bibby):

BROTHER x=−1

OpenStudy (anonymous):

hold up

OpenStudy (anonymous):

i got it

OpenStudy (bibby):

-1*

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