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OpenStudy (anonymous):
OpenStudy (anonymous):
these are the answers i have to match it with 18 all reall numbers 15 2 no real solution -9
OpenStudy (anonymous):
@bibby
OpenStudy (bibby):
1. to undo a square root, square both sides.
\(\huge \sqrt{4x+1}=3\)
\(\huge \sqrt{4x+1}^2=3^2\)
\(\huge 4x+1=9\)
OpenStudy (anonymous):
is it 2?
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OpenStudy (bibby):
yeah
OpenStudy (anonymous):
yeaaa lol okay can u help with problem 2
OpenStudy (bibby):
fractional exponents are roots. they work like this:
\(\huge a^{\frac{1}{2}}=\sqrt{a}\)
\(\huge (a+1)^{\frac{1}{3}}=\sqrt[3]{a}\)
OpenStudy (bibby):
so start by getting the variable we want to isolate on one side
OpenStudy (anonymous):
is example 4 9?
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OpenStudy (bibby):
yeah
OpenStudy (anonymous):
-9 rite?
OpenStudy (anonymous):
cause that wa answer they have on here they dnt have a regular 9
OpenStudy (bibby):
\(\large\sqrt{x-6}-3=0\) we want to get 3 on the other side. add 3 to both
\(\large\sqrt{x-6}=3\) we want to get ride of the square root so we square both sides
\(\large{x-6}=9\) add 6 to both sides
\(\large{x}=15\)
OpenStudy (bibby):
my bad
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OpenStudy (anonymous):
for promblem 2 did u get 18
OpenStudy (bibby):
\(\large4-\sqrt{7-y}=0\)
\(\large4=\sqrt{7-y}\)
what comes next?
OpenStudy (anonymous):
-9?
OpenStudy (bibby):
yeah. please do the actual work so that I can see you're learning
I hate it when I help people and they haven't taken anything away from it at the end
OpenStudy (anonymous):
okay i was im doing problem 3 now
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OpenStudy (anonymous):
problem looks like no solution
OpenStudy (anonymous):
im doing the work now
OpenStudy (anonymous):
okay problem 5 is 18
multiply through by 6
12a^(1/3) = 6
divide by 12
a^(1/3)=1/2
cube both sides
a=(1/2)^3=1/8