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Find the inverse of the function. F(x)=6-3x
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So far I have f(x)=x-6/-3... I need it in y=mx+b.
@DangerousJesse @Nnesha
F(x) = y y=x-6/3 3y=6-x 3y-6=-x x=6-3y F'(x) = 6 -3x
|dw:1410622533397:dw| heres what i have..
\(\large y=6-3x\) \(\large y-6=-3x\) \(\large 3x=6-y\) \(\large x=\dfrac{6-y}{3}\) \(\large hence~~f'(x)=\dfrac{6-x}{3}\)
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but how can i get rid of the 3 in the denominator? can i still verify the inverse with the 3, or will i have to do something with it?
it can be written as further \(\large f'(x)=2-\dfrac{x}{3}\)
nothing can be done with 3 ,it resides
okay, thanks!
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