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Prove that:- cosAsin(B-C) + cosBsin(C-A) + cosCsin(A-B) =0
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expand sin (x-y) = sin x cos y - cos x sin y all 3 sin terms
oh wait
if i am not wrong , everything will cancel out
yup
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cool :)
thank you
welcome ^_^
hehe , i was doing cos c + cos d and all of that
Infact you can do that..
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That is simpler to apply here.
You must know that: \[2\cos(x)\sin(y) = \sin(x+y) - \sin(x-y)\]
yeah i know :)
yes yes we can apply that , also cool:)
Multiply and divide by 2 first, and then apply the formula there, the terms will easily cancel out...
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always good to know alternate methods :)
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