Question

solve for g in the equation: S=1/2gt^2
i am really confused and i dont know where to begin pleaseee help!!!!

Answer 1

is it \[s=\frac{1}{2\cdot g \cdot t^2} ?\]

Answer 2

I believe that's the equation for the distance fallen of a dropped object.
So it is distance = .5*g*t^2

The value of 'g' is 9.8 meters per sec^2

Answer 3

or \[\frac{1}{2}\cdot g \cdot t^2\]

Answer 4

that's it bakur

Answer 5

http://www.algebra.com/algebra/homework/formulas/Geometric_formulas.faq.question.237561.html