Question

Testing

Answer 1

Equation is: \(\normalsize\color{black}{x=A(y-h)^2+k}\)
Let's find for \(y\)
\(\normalsize\color{black}{x-k=A(y-h)^2}\) First, let's move the K to the LHS
\(\normalsize\color{black}{\frac{x-k}{A}=(y-h)^2}\) Then, lets divide both sides by \(A\)
\(\normalsize\color{black}{\pm\sqrt{\frac{x-k}{A}}=y-h}\) Square root the number to get \(y-h\). remember, it can be positive or ngative
\(\normalsize\color{black}{\pm\sqrt{\frac{x-k}{A}}+h=y}\) Move the \(h\) to the LHS
Now we have:
\[y=\pm\sqrt{\frac{x-k}{A}}+h\]

Answer 2

Yay, \(LaTeX\) works, \(\text{YAY}\)

Answer 3

You forgot the \ in front of LaTeX. \(\LaTeX\)