Testing

Question

Testing

ahsome · Answer

Equation is: $\normalsize\color{black}{x=A(y-h)^2+k}$
Let's find for $y$
$\normalsize\color{black}{x-k=A(y-h)^2}$          First, let's move the K to the LHS
$\normalsize\color{black}{\frac{x-k}{A}=(y-h)^2}$               Then, lets divide both sides by $A$
$\normalsize\color{black}{\pm\sqrt{\frac{x-k}{A}}=y-h}$               Square root the number to get $y-h$. remember, it can be positive or ngative
$\normalsize\color{black}{\pm\sqrt{\frac{x-k}{A}}+h=y}$                 Move the $h$ to the LHS
Now we have:
$$y=\pm\sqrt{\frac{x-k}{A}}+h$$

ahsome · Answer

Yay, $LaTeX$ works, $\text{YAY}$

e.mccormick · Answer

You forgot the \ in front of LaTeX.  $\LaTeX$