WILL FAN AND MEDAL!! Three terms of a geometric sequence are shown. f(1) = 1, f(3) = 9, f(6) = –243 Which recursive formula could define the sequence? A)f(n + 1) = 9f(n) B) f(n + 1) = –9f(n) C) f(n + 1) = 3f(n) D) f(n + 1) = –3f(n)
how can we get from f(1) to f(3)? that is 1 to 9 one possibility is that common ratio = 3 1 --> 1*3 --> 1*3*3 but the sixth term is negative so looks more like common ratio = -3 what do you think?
umm. i really dont know cause i just started on this topic and its a bit confusing
f(1) means the first function that is 1 f(3) = third = 9 f(n) means the value of the function when variable = n f(n+1) means the value of the next one after n so f(n+1) = 3f(n) means that for a function you get the next one by multiplying it by 3 in our case the number is -3 so which option is correct?
we can work out all the terms by multiplying by -3:- 1, -3, 9 , -27, 81, -243 that fits - the 6th term is -243
so its D then?
yes
oh ok, thanks for the help :)
yw
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