Question

1 over the cube root of the quantity of x to the negative sixth power

Answer 1

@Basher that is unnecessary.
@grray7 \(\Huge\bf \color{yellow}{Welcome~to~OpenStudy!!}\hspace{-310pt}\color{cyan}{Welcome~to~OpenStudy!!}\hspace{-307.1pt}\color{midnightblue}{Welcome~to~\color{purple}{Open}}\color{blue}{Study!!!!}\)

Answer 2

good reply basher

Answer 3

recall that fractional exponents are roots like \(a^{1/2}=\sqrt{a}\)
\(\large a^{1/4}=\sqrt[4]{a}\)

and that powers raised to powers get multiplied like \((a^m)^n=a^{m*n}\)

Answer 4

\(\large \sqrt[3]{x^6} = x^2\)

Answer 5

Understand?

Answer 6

yeah, thanks. And BTW's I like your profile. :)

Answer 7

Your Welcome!!! Mine?

Answer 8

yes, @YanaSidlinskiy

Answer 9

\(\huge \frac{1}{\sqrt[3]{x}^{-6}}=\sqrt[3]{x}^{6}=x^{\frac{1}{3}^6}\)

Answer 10

Thanks Bibby

Answer 11

Lol, thanx!! @grray7

Answer 12

yep

Answer 13

@yanasidlinskiy

Answer 14

Did u need me? grray7

Answer 15

I do now, if you could help me out with \[\sqrt{-3x-10}=x\]