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OpenStudy (anonymous):
How do I graph \[y + x \ge 0\]
I know its line, but I can't explain why its sloping the way it does.
OpenStudy (anonymous):
Here is it's line in geogebra
OpenStudy (gorv):
y+x>=0
first solve
y+x=0
OpenStudy (gorv):
and we have to take value on this line and above
OpenStudy (gorv):
as equal to sign is there so line will also be included
y+x=0
y=-x is our line can you plot it ??
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OpenStudy (anonymous):
Sorry, I went to the bathroom. Hold on a second.
OpenStudy (anonymous):
(0, 0) (1, -1) (2, -2) and so on.
OpenStudy (gorv):
yeah can you draw the line ???
OpenStudy (anonymous):
|dw:1411322087128:dw|
OpenStudy (anonymous):
That?
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OpenStudy (gorv):
yeah
OpenStudy (gorv):
this is y+x=0
OpenStudy (anonymous):
So, how did you get y = -x?
OpenStudy (gorv):
we have to take y+x=0 and y+x>0 both
OpenStudy (gorv):
y+x>=0 we had so its minimum value is
y+x=0
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OpenStudy (anonymous):
Okay.
OpenStudy (gorv):
now move x on other side
OpenStudy (gorv):
u got it right ???
OpenStudy (anonymous):
(-1, 1) (-2, 2) ect.
OpenStudy (anonymous):
I need to be able to explain why I did what to get the answer.
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OpenStudy (gorv):
okay
we had
x+y>=0
OpenStudy (anonymous):
Yes.
OpenStudy (gorv):
so we need to start with minimum possible value
OpenStudy (anonymous):
so our y intercept is 0
OpenStudy (gorv):
like if a >=3
what is its minimum value
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OpenStudy (gorv):
a=3ok ???
OpenStudy (gorv):
and after that 4 , 5, 6, 7, and so on ...
OpenStudy (anonymous):
Our minimum value is 3, because a is greater than or equal to 3
OpenStudy (gorv):
so min value is y+x=0
so we draw this line such that point on line sum to zero
like (0,0) 0+0=0
(1,-1) 1-1=0
and if we put any point in line above these point our ans will be greater than zero