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Mathematics 19 Online
OpenStudy (anonymous):

Help! I'm stuck!

OpenStudy (anonymous):

How do I graph \[y + x \ge 0\] I know its line, but I can't explain why its sloping the way it does.

OpenStudy (anonymous):

Here is it's line in geogebra

OpenStudy (gorv):

y+x>=0 first solve y+x=0

OpenStudy (gorv):

and we have to take value on this line and above

OpenStudy (gorv):

as equal to sign is there so line will also be included y+x=0 y=-x is our line can you plot it ??

OpenStudy (anonymous):

Sorry, I went to the bathroom. Hold on a second.

OpenStudy (anonymous):

(0, 0) (1, -1) (2, -2) and so on.

OpenStudy (gorv):

yeah can you draw the line ???

OpenStudy (anonymous):

|dw:1411322087128:dw|

OpenStudy (anonymous):

That?

OpenStudy (gorv):

yeah

OpenStudy (gorv):

this is y+x=0

OpenStudy (anonymous):

So, how did you get y = -x?

OpenStudy (gorv):

we have to take y+x=0 and y+x>0 both

OpenStudy (gorv):

y+x>=0 we had so its minimum value is y+x=0

OpenStudy (anonymous):

Okay.

OpenStudy (gorv):

now move x on other side

OpenStudy (gorv):

u got it right ???

OpenStudy (anonymous):

(-1, 1) (-2, 2) ect.

OpenStudy (anonymous):

I need to be able to explain why I did what to get the answer.

OpenStudy (gorv):

okay we had x+y>=0

OpenStudy (anonymous):

Yes.

OpenStudy (gorv):

so we need to start with minimum possible value

OpenStudy (anonymous):

so our y intercept is 0

OpenStudy (gorv):

like if a >=3 what is its minimum value

OpenStudy (gorv):

a=3ok ???

OpenStudy (gorv):

and after that 4 , 5, 6, 7, and so on ...

OpenStudy (anonymous):

Our minimum value is 3, because a is greater than or equal to 3

OpenStudy (gorv):

so min value is y+x=0 so we draw this line such that point on line sum to zero like (0,0) 0+0=0 (1,-1) 1-1=0 and if we put any point in line above these point our ans will be greater than zero

OpenStudy (anonymous):

Okay! Thanks! Makes more sense now.

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