Question

.

Answer 1

yea im alright

Answer 2

i heard of them

Answer 3

what do you got for a question?

Answer 4

nope

Answer 5

i mean nope as in no limit

Answer 6

yes

Answer 7

the function is really
\[ f(x) = \left\{
\begin{array}{lr}
-1 & : x <\frac{1}{2}\\
1& : x >\frac{1}{2}
\end{array}
\right.\]

Answer 8

if \(x<\frac{1}{2}\) then \(|2x-1|=1-2x\) and
\[\frac{|2x-1|}{2x-1}=\frac{1-2x}{2x-1}=-1\]

Answer 9

similarly if \(x>\frac{1}{2}\) then
\(|2x-1|=2x-1\) and \(\frac{2x-1}{2x-1}=1\)

Answer 10

so it really looks like this

Answer 11

and the limit from the left is \(-1\) the limit from the right is \(1\) and since \(-1\neq 1\) there is no limit

Answer 12

When working with limits, it helps to look at the graph of the functions given.