Mathematics
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OpenStudy (anonymous):
y-3x=13 I don't know how to do this :(
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OpenStudy (triciaal):
what are you suppose to do ? make y the subject?
we really can't help if you don't put the instructions.
OpenStudy (anonymous):
Solve the literal equation for y
OpenStudy (anonymous):
It just means have y alone equal to an expression.
y=mx+n
OpenStudy (anonymous):
So all you need to do in the equation you posted is add 3x to both sides.
OpenStudy (anonymous):
which would be 9x and 21?
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OpenStudy (anonymous):
y-3x=13
y-3x+3x=13+3x
y+0=13+3x
y=3x+13
OpenStudy (anonymous):
Sorry I don't understand how to do this at all :/
OpenStudy (anonymous):
Do you know how to solve basic equations?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
Can you solve this for x?
2x=4
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OpenStudy (anonymous):
4-2
OpenStudy (anonymous):
= 2x
OpenStudy (anonymous):
To have x alone you have to divide both sides by 2
OpenStudy (anonymous):
2x divided by 2 is x
4 divided by 2 is 2
2x=4 /:2
x=2
OpenStudy (anonymous):
Oh thanks :)
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OpenStudy (anonymous):
Now do this for me:
3x-1=5
OpenStudy (anonymous):
Solve for x, make sure it's alone at the end.
OpenStudy (anonymous):
3x+3x= 5+3x
0x+ 1 = 5+3x
5+3x=8+1+ 9x ?
OpenStudy (anonymous):
3x-1=5 / add 1 to both sides
3x-1+1=5+1
3x+0=6
3x=6 /divide both sides by 3 to have x alone
x=2
OpenStudy (anonymous):
Remember that you can't add 2x+3 to have 6x, they are different factors
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OpenStudy (anonymous):
I don't get it still
OpenStudy (anonymous):
On one side you want numbers with x attached to them, on the other just numbers
OpenStudy (anonymous):
Do this expression, not an equation this time. Just add those up.
2x+4x+5+7
OpenStudy (anonymous):
18
OpenStudy (anonymous):
You can only add up numbers with an x, and regular numbers
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OpenStudy (anonymous):
6x+12
OpenStudy (anonymous):
oh
OpenStudy (anonymous):
Do another expression:
5x+2-3x+1
OpenStudy (anonymous):
8x+3
OpenStudy (anonymous):
Notice the minus on the 3x
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OpenStudy (anonymous):
Algebra 1 is too hard:/
OpenStudy (anonymous):
If you want, you can rewrite them, the order doesn't matter in an expression
OpenStudy (anonymous):
5x-3x+2+1
2x+3
OpenStudy (anonymous):
It's easier to see it that way.
OpenStudy (anonymous):
2y-18x=-26
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OpenStudy (anonymous):
Add 18x to both sides
OpenStudy (anonymous):
18x=-26
+18x =18x
0x 34x
OpenStudy (anonymous):
then divide 2 to both sides?
OpenStudy (anonymous):
its wrong isn't it
OpenStudy (anonymous):
2y-18x+18x=-26+18x
2y+0=26+18x
2y=26+18x
now divide by 2, yes.
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OpenStudy (anonymous):
52 and 17?
OpenStudy (anonymous):
If you divide every individual bit by 2, what do you get
2y, 26 and 18x
OpenStudy (anonymous):
2y=26+18x /:2
y=13+6x
does that make sense?
OpenStudy (anonymous):
not at all
OpenStudy (anonymous):
Which is why i wanted to practice some more basic things before we move to the exercises you show me.
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
In equations, the point is to get the numbers with the x to one side, and regular numbers to the other side.
OpenStudy (anonymous):
4x+2=1+3x
OpenStudy (anonymous):
To move them around, we need to either add or subtract that same number
OpenStudy (anonymous):
For example, to move that 3x with the 4x
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OpenStudy (anonymous):
We need to subtract 3x from both sides
OpenStudy (anonymous):
- 2 to both sides?
OpenStudy (anonymous):
oh
OpenStudy (anonymous):
4x+2-3x=1+3x-3x
OpenStudy (anonymous):
+3x-3x is equal to zero, so it gets cancelled out
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OpenStudy (anonymous):
4x+2-3x=1
OpenStudy (anonymous):
Now we need to move the two, move it for me.
OpenStudy (anonymous):
2
-2
OpenStudy (anonymous):
4x+2-3x=1
subtract 2 from both sides of the equation
OpenStudy (anonymous):
simply add -2 to both sides
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OpenStudy (anonymous):
2 =3x
-2 -2
OpenStudy (anonymous):
4x+2-2-3x=1-2
4x-3x=-1
1x=-1
OpenStudy (anonymous):
Also, writing x and 1x is the same.
OpenStudy (anonymous):
Let's try another one.
OpenStudy (anonymous):
3x+1=2
How would you have 3x alone in here?
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OpenStudy (anonymous):
-1 to both sides
3x+1=2
3x -1= -1
3x= 0=1
x=4
OpenStudy (anonymous):
Remember that you are removing 1 from both sides without changing any numbers, just tuck them in there
OpenStudy (anonymous):
3x+1-1=2-1
3x=1
OpenStudy (anonymous):
x=1?
OpenStudy (anonymous):
Now if you wanted x alone without the 3, you would have to divide both sides by 3
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OpenStudy (anonymous):
3x divided by 3 is x
1 divided by 3 is a third
OpenStudy (anonymous):
\[3x=1\]
\[x=\frac{ 1 }{ 3 }\]
OpenStudy (anonymous):
I think i'm starting to get it now
OpenStudy (anonymous):
Great :)
OpenStudy (anonymous):
5x-4=10-2x
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OpenStudy (anonymous):
5x -4=10-2x
5x +4= +4-2x
5x +0= 14-2x
5x=0=12
OpenStudy (anonymous):
I get the beginning of it I think but idk the ending
OpenStudy (anonymous):
5x-4=10-2x
5x-4+4=10-2x+4
you added 4 right?
OpenStudy (anonymous):
I did the first time and got 8x
OpenStudy (anonymous):
10-8x
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OpenStudy (anonymous):
There is no need to show that -4+4 is 0, just eliminate it from the start
Reorder the positions so you see what's numbers and what's x's
5x=10+4-2x
OpenStudy (anonymous):
5x=14-2x
OpenStudy (anonymous):
5x=12x
OpenStudy (anonymous):
14 is a number, 2x is an x
OpenStudy (anonymous):
we need to move that -2x to the x's side.
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OpenStudy (anonymous):
In other words, to have 14 alone, we need to find a way how can we have a zero there
OpenStudy (anonymous):
If we add 2x it's going to be
14-2x+2x
14-0
14
OpenStudy (anonymous):
But since we added 2x, we must also add it on the other side
OpenStudy (anonymous):
5x+2x=14-2x+2x
7x=14-0
7x=14
OpenStudy (anonymous):
How would you isolate x in here?
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OpenStudy (anonymous):
divide it by 7x
OpenStudy (anonymous):
If you were to divide by 7x, you would get this:
\[\frac{ 7x }{ 7x }=\frac{ 14 }{ 7x }\]
\[1 = \frac{ 2 }{ x }\]
OpenStudy (anonymous):
But since we still want x, we only divide by 7.
OpenStudy (anonymous):
\[\frac{ 7x }{ 7 } = \frac{ 14 }{ 7 }\]
x=2
OpenStudy (anonymous):
Isolate x in here:
3x=9
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OpenStudy (anonymous):
3
OpenStudy (anonymous):
x is indeed equal to 3
OpenStudy (anonymous):
2y+3y+8x-3x+1+4