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How does 48 squared equal 4*3^2?
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\[\sqrt{48}= 4\sqrt{3} \]
\[48=16\times 3\] not \[4\times 9\]
\[\sqrt{16\times 3}=\sqrt{16}\sqrt3=4\sqrt3\]
Oh, and so the three stays squared because you can't reduce it or "resquare" it anymore?
the 3 stays in because 3 is not a perfect square, i.e. the square root of 3 is an irrational number, not an integer
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whereas even i know that the square root of 16 is 4
Haha, alright, thanks :) One questio though, could you set it up 48 equals 24 x 2?
Or since both are irrational numbers, you can't set it up that way?
look at first 2 lines 48 squared is not the same as square root of 48
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