Question

Factor.
8x^3+14x^2-15x

Answer 1

start by taking out an x as a common factor

\[x(8x^2 + 14x - 15)\]

next you need to multiply 8 and -15 = -120

find the factors that add to 14, the larger is positive so 20 and - 6

then you get

\[\frac{x(8x + 20)(8x - 3)}{8}\]

remove the common factors from the binomials

\[\frac{x \times 4(2x + 5)\times 2(4x -3)}{8}\]

cancel the common factors

leaving

x(2x + 5)(4x - 3)

Answer 2

Thank You!