Find the equation, in standard form, of the line passing through the points (5,1) and (-2,3). how do I figure this out? do I have to find the slope first?
the equation of a line is y=mx+b so find m (slope) using the points given m= y2-y1/x2-x1=(3-1)/(-2-5)=2/-7=-2/7 so you have y=-2/7x+b to find b, plug in either coordinates given for x and y and isolate for b 1=-2/7(5)+b b=1+(10/7) b=17/7 so the equation is y=-2/7x + 17/7
the slope is -2/7 I think but what do I do after that?
yes that is the right slope. see my solution above for the rest of the steps ^^^
forgot the last step. to make it standard form, just make it equal to zero. so y + 2/7x - 17/7 = 0
I understand it now. Except the answer isn't an option on my homework ?? Is there another way to do this?
oh all they did on your answer sheet is make everything into whole numbers
so just multiply your entire equation by 7 to get rid of the fractions: (7)y + (7)2/7x - (7)17/7 = (7)0 (multiply each term by 7) 7y + 2x -17 = 0 (rearrange if needed) 2x + 7y = 17 (same as B)
Where does the 7 come from?
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