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You show me your work, please. Just isolate y from the second one and plug it into the first one to solve for x. Then plug that x back to the isolate y expression to get y . And you are done.
How many problems do you have here? 2, right? do the first one only. Don't mix them up.
ha!! OOOOOOOk do steps above, what I said, and show me your work.
\[\begin{cases}2x+\color{red}{y}=5\\\color{red}{y}+3 =2x\end{cases}\] 1) isolate y from the second one: \[\color{red}{y}=2x-3\] Plug that y into the first one \[2x +\color{red}{y} =5~~becomes~~2x+\color{red}{2x-3}=5\] so the answer is??
NOOOOOOOOOOO
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read my guidance and answer carefully, pleease.
yes
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