find the equation of the line through the given pair of points in standard form using only integers
(5,-3) and (-2,4)
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OpenStudy (anonymous):
standard form is ax+bx+cx
OpenStudy (anonymous):
stadard form is Ax+ Bx=c
OpenStudy (anonymous):
yes, don't know why I put x on but you first find the slope. the formula is y2-y1/x2-x1
OpenStudy (anonymous):
4-(-3)/-2-5= 7/-7= -1 negative 1 is the slope
OpenStudy (anonymous):
put the equation in point slope form y-(-3)=-1(x-5)= y-(-3)=-1x+5
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OpenStudy (anonymous):
write in slope intercept form by just add-3 to both sides and you get y=-1x+8
add 1x to both sides and you get the equation in standard form which is 1x+y=8
OpenStudy (anonymous):
subtract 3
OpenStudy (anonymous):
you add 3 because the 3 is a negative
OpenStudy (anonymous):
no it turns positive
OpenStudy (anonymous):
it turns positive when you add it to the other side of the equation
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OpenStudy (anonymous):
y--3=y+3 hence you subtract by 3 to cancel it out in that term
OpenStudy (anonymous):
where did you get the +3 at the end of the equation?