I need to find the equation for the plane, and it contains the lines r1(t)= and r2(t)=. Then I have to write the equation in the form ax+by+cz=d.

Question

I need to find the equation for the plane, and it contains the lines r1(t)= <1+2t,-2+3t,4> and r2(t)=<3-5t,-1+17t,-28t>. Then I have to write the equation in the form ax+by+cz=d.

ganeshie8 · Answer

take the cross product of `direction vectors of lines` to get the normal to the plane

ganeshie8 · Answer

r1(t)= <1+2t,-2+3t,4> and r2(t)=<3-5t,-1+17t,-28t>. direction vector of r1 = (2, 3, 0) direction vector of r2 = (-5, 17, -28) take the cross product, what do u get ?

ganeshie8 · Answer

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