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Hello can anybody help please. Define the length of the curve of sinx from 0 to 2*pi.
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\[L=\int_a^bdS\] where \(dS=\sqrt{a+\left[f'(x)\right]^2}~dx\). \[L=\int_0^{2\pi}\sqrt{1+\cos^2x}~dx\]
Sorry, that \(a\) should be a 1.
Can you please solve the integral also? thats where i got stuck.
It does not have an elementary result, I'm afraid... The best you can do (unless you're familiar with complete elliptic integrals) is to find an approximation.
ok, thanks a lot!
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