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Trigonometry. Will medal and fan. (Pre-calculus)
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\[Cos \theta = \frac{ 1 }{ 2 } , Sin \theta < 0; \] find Csc and Tan
I know the answers, no idea how to get them.
where is angle theta? which quadrant is it located in?
seems to be quadrant four.
correct
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now we use the identity cos^2 + sin^2 = 1 to find sine when cos(theta) = 1/2
what do you get?
square root of three over two?
it's negative because we're told that sin(theta) < 0
oh okay since sin is y/r r=2 and y=square root of three and x is going to equal one based on the cos definition
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oh okay so y = negative square root of three
and then I just use the definitions (csc=r/y and tan=y/x)
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