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Mathematics 18 Online
OpenStudy (darkbluechocobo):

Help with factor theorem

OpenStudy (darkbluechocobo):

OpenStudy (anonymous):

what do u think ?

OpenStudy (anonymous):

http://prntscr.com/4rtx1u

OpenStudy (anonymous):

f(2)=0 and f(-1)=0 thus (x-2) and (x+1) are factors right ? ( from factor theorm )

OpenStudy (darkbluechocobo):

well Im just confused how to start it. I know how synthetic division works just not factor theorem

OpenStudy (darkbluechocobo):

Yes

OpenStudy (darkbluechocobo):

then i assume you have to factor f(x)?

OpenStudy (anonymous):

yep , u have now too factors right ?

OpenStudy (anonymous):

two*

OpenStudy (darkbluechocobo):

Yes

OpenStudy (darkbluechocobo):

(x-2),(x+1) then would it be x^2 for the first part

OpenStudy (anonymous):

ok so u could do the rest ? or u dint understand factor theorem ?

OpenStudy (darkbluechocobo):

Like.im confused with the x-c

OpenStudy (anonymous):

if u have a function f(x) and c is any number , then if f(c)=0 , then remainder of f(x)/x-c is zero right ? thus x-c is a factor

OpenStudy (darkbluechocobo):

so for example in this c is -1?

OpenStudy (anonymous):

yes in the example there is two value for c , c=-1 and c=2 any way since we have two factors x-2 and x+1 so 2 options we have B or D but as u can see , D is not completely factored thus the answer is B

OpenStudy (darkbluechocobo):

well could you go with me through how to factor f(x) :/

OpenStudy (anonymous):

well i have to go now :( but u showed use factor theorem , here it is http://prntscr.com/4rtx1u maybe @praxer wanna continue this

OpenStudy (darkbluechocobo):

ill be right back

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